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1.7 Finding parts of angles 1 2 2 1 Find (a) 5 of the measure of a rt. /; (b) 3 of the measure of a st. /; (c) 2 of 31 ; (d) 10 of 70 20 .

In other words, the response of the system to 6(n - k - 1) is not equal to the response of the system to 6(n - k) delayed by 1. Therefore. this system is shift-varying.

In Solved Problem 7.25, it is given that ABCD in a figure like Fig. 7-9 is a parallelogram, and we must AF AE prove that . To prove this proportion, it is necessary to find similar triangles whose sides are BC FB in the proportion. This can be done simply by selecting the triangle whose letters A, E, and F are in the numerators and the triangle whose letters B, C, and F are in the denominators. Hence, we would prove nAEF , nBCF. AE BC Suppose that the proportion to be proved is . In such a case, interchanging the means leads to AF FB AE AF . BC FB The needed triangles can then be selected based on the numerators and the denominators. AE AF Suppose that the proportion to be proved is . Then our method of selecting triangles could not AD FB be used until the term AD were replaced by BC. This is possible, because AD and BC are opposite sides of the parallelogram ABCD and therefore are congruent.

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Let Tr.1 be a linear system, not necessarily shift-invariant, that has a response h k ( n )to the input 6 ( n - k). Derive a test in terms of k k ( n )that allows one to determine whether or not the system is stable and whether or not the system is causal.

(a) The response of a linear system to an input ~ ( nis)

PRINCIPLE 1: PRINCIPLE 2: PRINCIPLE 3:

The derivative is so important in all parts of pure and applied mathematics that we must devote a great deal of effort to nding formulas for the derivatives of various kinds of functions. If the limit in the above de nition exists, the function f is said to be differentiable at x, and the process of calculating f is called differentiation of f . EXAMPLES

Therefore. the output may be hounded as follows:

Corresponding angles of similar triangles are congruent (by the definition). Corresponding sides of similar triangles are in proportion (by the definition). Two triangles are similar if two angles of one triangle are congruent respectively to two angles of the other.

the output will be bounded, and the system is stable. Equation (1.23) is a necessary condition for stability. To establish the sufficiency of this condition, we will show that if this summation is not finite, we can find a bounded input that will produce an unbounded output. Let us assume that hk(n) is bounded for all k and n [otherwiue the system will be unstable. because the response to the bounded input S(n - k) will be unbounded]. With hi(tl) bounded for all k and n, suppose that the sum in Eq. (1.23) is unbounded for some n, say n = no. Let x(n) = s g n ( h , ( n ~ ) l that is,

Fig. 7-10

which, by assumption, is unbounded. Therefore, the system is unstable and we have established the sufficiency of the condition given in Eq. (1.23).

(a) Let f (x) = 3x + 5 for all x. Then, f (x + h) = 3(x + h) + 5 = 3x + 3h + 5 f (x + h) f (x) = (3x + 3h + 5) (3x + 5) = 3x + 3h + 5 3x 5 = 3h 3h f (x + h) f (x) = =3 h h Hence, f (x) = lim

PRINCIPLE 4:

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